We have seen average calculation using Aggregation.
In this post, we will see how to calculate a sum of the set of values from a field. It works quite similar to avg
function.
- Aggregation can only be performed on numerical fields like Integers and Floats.
-
sum
function calculates the sum of the set of numbers. - It can be performed with or without filters.
- The
distinct
filter gives the sum of unique rows. - The
where
clause selects matching rows with specific field values.sum
function then calculates the sum of the selected rows.
We will work with the same schema.
type AggObj {
intFld: Int
floatFld: Float
}
Let’s use the same 7 records from the previous post.
mutation {
upsert(
values: {
AggObj: [
{ intFld: 1, floatFld: 1.1 }
{ intFld: 2, floatFld: 1.2 }
{ intFld: 3, floatFld: 1.3 }
{ intFld: 4, floatFld: 1.4 }
{ intFld: 4, floatFld: 1.4 }
{ intFld: 3, floatFld: 1.3 }
{ intFld: 1, floatFld: 1.1 }
]
}
) {
id
}
}
Sample Query
Let’s find out the sum of all the floatFld
values from the 7 records.
{
aggregate {
aggObj {
floatFld {
sum
}
}
}
}
#result
{
"data": {
"aggregate": {
"aggObj": {
"floatFld": {
"sum": 8.8
}
}
}
}
}
Now, we will use the distinct
filter to find out the sum of unique values. The below query considers repeated values from floatFld
as one value. So the count of records becomes 4 instead of 7.
The sum becomes (1.1+1.2+1.3+1.4) = 5
{
aggregate {
aggObj {
floatFld {
sum(distinct: true)
}
}
}
}
#result
{
"data": {
"aggregate": {
"aggObj": {
"floatFld": {
"sum": 5
}
}
}
}
}
Let’s find out the sum of the floatFld
values where intFld
values are 1.
Sum = 1.1 + 1.1 = 2.2
{
aggregate {
aggObj (where: "intFld=1") {
floatFld {
sum
}
}
}
}
#Result
{
"data": {
"aggregate": {
"aggObj": {
"floatFld": {
"sum": 2.2
}
}
}
}
}
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